Chemistry - Thermodynamics - I Question with Solution | TestHub

For adiabatic conditions, $P{V}^{\gamma }=$ Constant $P_1{V}_1^{\gamma }=P_2{V}_2^{\gamma };V_2=\frac{1}{2}{V}_1$ $P_2=P_1{\left(\frac{V_1}{V_2}\right)}^{\gamma }$ [For diatomic gas, $\gamma =1.4$ ] $P_2=P_1{\left(\frac{V_1\times 2}{V_1}\right)}^{1.4}$ $P_2=P_1(2{)}^{1.4}=(2{)}^{1.4}P$