Chemistry - Thermodynamics - I Question with Solution | TestHub

System is in a closed container. So there will be no heat transfer. Therefore the heat is $q=0$. Now liquid is stirred with a paddle to increase the temperature which increases the internal energy $\Delta E$ of the system. $$\begin{array}{rl}& \Delta \mathrm{E}=n\mathrm{C}\Delta \mathrm{T}\\ & \Delta \mathrm{E}\ne 0\end{array}$$ Work is also done on the system when started with a paddle. $$\begin{array}{c}\mathrm{W}\ne 0\\ \Delta \mathrm{E}=q+\mathrm{W}=0+\mathrm{W},\Delta \mathrm{E}=\mathrm{W}\\ \Delta \mathrm{E}=\Delta \mathrm{W}\ne 0,q=0\end{array}$$