Chemistry - Thermodynamics - I Question with Solution | TestHub

Correct option is (D) $\to {\mathrm{T}}_1={\mathrm{T}}_2$ (Paints on isothermal curve)

→ Area under the curve give work done by system during expansion

${\mathrm{W}}_{\text{Iso }}>{\mathrm{W}}_{\text{adiabetic }}$

(as area under isothermal curve is more)

with sign

$-{\mathrm{W}}_{\text{Iso }}<-{\mathrm{W}}_{\text{adiabetic }}$

→ In adiabatic expansion $\mathrm{q}=0$, as volume Increases, Internal Energy of system decreases ( $\Delta \mathrm{U}=\mathrm{W}$ ) hence temperature decreases.

In Isothermal expansion, Temperature remains constant hence Internal energy remains constant as it depends only on Temperature

So $\Delta {\mathrm{U}}_{\text{Isothermal }}>\Delta {\mathrm{U}}_{\text{adiabetic }}$