Chemistry - Thermodynamics - 1 Question with Solution | TestHub

ChemistryThermodynamics - 1Adiabatic Process/PolytropicEasy2 minPYQ_2020
ChemistryEasynumerical

1Mole ofCO2gas at300 Kexpanded under the reversible adiabatic condition such that its volume becomes27times. The magnitude of work doneinkJ/molis:
(Given γ=1.33 and Cv=25.10Jmol1K1forCO2)
report your answer by rounding it up to nearest whole number

Answer:
5.00
Solution:

Number of moles=1

T1=300 K

V2=27V1

TV1γ-1=T2V2γ-1

T1T2=V2V1r1

T2=30012713

T2=100 K

Adiabatic condition,q=0;ΔE=w=nCvT2T1

w=1×25.10100300=-5020J/mole

w=-5.02kJ/mole

Stream:NTA_ABHYASSubject:ChemistryTopic:Thermodynamics - 1Subtopic:Adiabatic Process/Polytropic
2mℹ️ Source: PYQ_2020

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