Chemistry - Thermodynamics - 1 Question with Solution | TestHub

$\because \text{ΔT}=\frac{\text{W}}{\text{nR}}$
$\therefore \text{Q}={\text{nC}}_{\text{p}}\text{(ΔT)}={\text{nC}}_{\text{p}}\frac{\text{W}}{\text{nR}}=\frac{{\text{C}}_{\text{p}}\text{W}}{\text{R}}$
${\text{C}}_{\text{p}}\text{=}\frac{\text{QR}}{\text{W}}\text{=}\frac{\text{500}\text{×}\text{2}}{\text{142}\text{.8}}\text{=}\text{7}$
${\text{C}}_{\text{p}}\text{=}\text{7, }$indicates that the gas is diatomic. Thus, it should be${\text{O}}_{\text{2}}$