Statement 1: The enthalpy of neutralization of any strong acid with any strong base in dilute solution is nearly the same, about -57.1 kJ per mole of water formed.
Statement 2: The net reaction in every such neutralization is H⁺(aq) + OH^-(aq) → H₂O(l).

Question

Statement 1: The enthalpy of neutralization of any strong acid with any strong base in dilute solution is nearly the same, about -57.1 kJ per mole of water formed.

Statement 2: The net reaction in every such neutralization is H⁺(aq) + OH^-(aq) → H₂O(l).

TestHub · Accepted Answer

Strong acids and strong bases are fully ionized in dilute solution, so whatever the acid-base pair, the only heat-changing step is H + + OH - → H 2 O, releasing about 57.1 kJ per mole of water (Statement 2 correct). This is exactly why the measured enthalpy of neutralization is nearly constant (Statement 1 correct), and Statement 2 explains Statement 1. Ans: (a).

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