Chemistry - Thermochemistry Question with Solution | TestHub
When 0.1 mole of C6H14(l) at 300 K is completely burned at constant pressure in some oxygen gas at 300 K, yielding products gaseous H2O, CO and CO2 at 700 K, the process yielding 75.16 kcal of heat to the surrounding. Given:
Δf H (kcal/mol): C6H14(l) = -40.0, CO2(g) = -94.0, CO(g) = -26.0, H2O(g) = -58.0
Molar heat capacity at constant pressure (cal/K-mol): CO(g) = 7.0, CO2(g) = 9.0, H2O(g) = 8.0
Assume that all Δr H are independent of temperature and R = 2 cal/K-mol.
How many moles of O2 are consumed in the combustion?
Options:
Answer:
Solution:
Products: CO2 0.4 mol, CO 0.2 mol, H2O 0.7 mol. O atoms = 2(0.4) + 0.2 + 0.7 = 1.7 mol. Each O2 supplies 2 O atoms, so O2 consumed = 1.7/2 = 0.85 mol. This is option (a).
