Chemistry - Thermochemistry Question with Solution | TestHub

ChemistryThermochemistryEnthalpy of ReactionMedium2 minQB
ChemistryMediummatching list

Match the following

Column I

Column II

P) 2H2O(g) → 2H2(g) + O2(g)

i) ΔH = ΔU + 2RT

Q) N2(g) + O2(g) → 2NO(g)

ii) ΔH = ΔU

R) 2SO2(g) + O2(g) → 2SO3(g)

iii) ΔH = ΔU - RT

S) 2NH3(g) → N2(g) + 3H2(g)

iv) ΔH = ΔU + RT

(Column I = Reaction; Column II = Relation)

Options:

Answer:
C
Solution:

Use ΔH = ΔU + Δng RT, counting gaseous moles only. P: Δng = 3 - 2 = +1, so ΔH = ΔU + RT, P-iv. Q: Δng = 2 - 2 = 0, so ΔH = ΔU, Q-ii. R: Δng = 2 - 3 = -1, so ΔH = ΔU - RT, R-iii. S: Δng = 4 - 2 = +2, so ΔH = ΔU + 2RT, S-i. Ans: P-iv; Q-ii; R-iii; S-i.

Stream:JEESubject:ChemistryTopic:ThermochemistrySubtopic:Enthalpy of Reaction
⏱ 2mℹ️ Source: QB

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