Enthalpy of neutralization of H 3 PO 3 acid is − 106.68 kJ / mol using NaOH . If enthalpy of neutralization of HCl by NaOH is − 55.84 kJ / mol . Calculate Δ H ionization of H 3 PO 3 into its

Question

Enthalpy of neutralization of H 3 ​ PO 3 ​ acid is − 106.68 kJ / mol using NaOH . If enthalpy of neutralization of HCl by NaOH is − 55.84 kJ / mol . Calculate Δ H ionization ​ of H 3 ​ PO 3 ​ into its ions

TestHub · Accepted Answer

H 3 ​ PO 3 ​ → 2 H + + HPO 3 2 − ​ Δ r ​ H = ? \displaylines 2 H + + O H − → 2 H 2 ​ O Δ r ​ H = − 55.84 × 2 = − 111.68 − 106.68 = Δ ion ​ H − 55.84 × 2 Δ ion ​ H = 5 kJ / mol ]

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