Chemistry - Thermochemistry Question with Solution | TestHub

ChemistryThermochemistryBond EnthalpyMedium2 minQB
ChemistryMediuminteger

Find bond enthalpy of (in ) using the following information:

Resonance energy of

 

Answer:
725
Solution:

image.png

700 + 500 – 2ε – 150 = –400

1200 – 2ε – 150 = –400

= 1450

ε = 725 kJ/mol

7 + 2 + 5 = 14 = 1 + 4 = 5 Ans.

Stream:JEESubject:ChemistryTopic:ThermochemistrySubtopic:Bond Enthalpy
2mℹ️ Source: QB

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