If C (diamond ) → C (graphite ) + X kJ mol − 1 C ( diamond ) + O 2 ( g ) → CO 2 ( g ) + Y kJ mol − 1 C (graphite) + O 2 ( g ) → CO 2 ( g ) + Z kJ mol − 1 at constant temperature. Then

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ChemistryThermochemistryEnthalpy of ReactionEasy2 minPYQ_2025

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If $C$ (diamond $) \to C$ (graphite $) + X kJ mol^{- 1}$ $C ($ diamond $) + O_{2} (g) \to CO_{2} (g) + Y kJ mol^{- 1}$ C (graphite) $+ O_{2} (g) \to CO_{2} (g) + Z kJ mol^{- 1}$ at constant temperature. Then

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Stream:JEESubject:ChemistryTopic:ThermochemistrySubtopic:Enthalpy of Reaction

⏱ 2mℹ️ Source: PYQ_2025

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