Chemistry - Thermochemistry Question with Solution | TestHub

The ionization enthalpy of${\mathrm{Na}}^{+}$formation from${\mathrm{Na}}_{\left(\mathrm{g}\right)}$is$495.8 \mathrm{kJ} {\mathrm{mol}}^{-1},$while the electron gain enthalpy of$\mathrm{Br}$is$-325.0 \mathrm{kJ} {\mathrm{mol}}^{-1}$. Given the lattice enthalpy of$\mathrm{NaBr}$is$-728.4 \mathrm{kJ} {\mathrm{mol}}^{ -1}$. The energy for the formation of$\mathrm{NaBr}$ionic solid is$\left(-\right)\_\_\_\_\_{10}^{-1} \mathrm{kJ} {\mathrm{mol}}^{-1}$