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ChemistryThermochemistryEnthalpy of ReactionMedium2 minPYQ_2021
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The Born-Haber cycle for KCl is evaluated with the following data:
ΔfHΘ for KCl=436.7kJmol1;ΔsubHΘ for K=89.2kJmol1;

Δionization HΘ for K=419.0kJ mol 1;Δelectron gain HΘ for Cl(g)=348.6kJmol1

Δbond HΘ for Cl2=243.0kJmol1
The magnitude of lattice enthalpy of KCl in kJmol-1 is (Nearest integer)

Question diagram: The Born-Haber cycle for KCl is evaluated with the following
Answer:
718
Solution:

So, ΔfHΘ=ΔfHΘKCl=Δsub HΘ+Δ1st ionisation HΘK+1/2ΔbondHΘCl2(g)+Δelectron gain HΘ+Δlattice HΘ-436.7=89.2+419+12243+-348.6+Δlattice HΘ

Δlattice HΘ=-717.8 kJ mole-1-718 kJ mole-1

Stream:JEESubject:ChemistryTopic:ThermochemistrySubtopic:Enthalpy of Reaction
2mℹ️ Source: PYQ_2021

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