Chemistry - Thermochemistry Question with Solution | TestHub

We know that

$∆\mathrm{H}=∆\mathrm{E}+\mathrm{P}∆\mathrm{V}$

In the reactions,${\text{H}}_2\left(\text{g}\right)+{\text{Br}}_2\left(\text{g}\right)\to 2\text{HBr}\left(\text{g}\right)$this is no change in volume or$∆\mathrm{V}=0$

So,$∆\mathrm{H}=∆\mathrm{E}$for this reaction