Chemistry - Thermochemistry Question with Solution | TestHub

$\Delta {\text{H}}_{\text{solu}}=\Delta {\text{H}}_{\text{hydration}}+\Delta {\text{H}}_{\text{Lattice}}$

$1=\Delta {\text{H}}_{\text{hydration}}+180$

$\Delta {\text{H}}_{\text{hydration}}=-179\text{ kcal}{\text{ m}}^{-1}$

$\Delta {\text{H}}_{\text{hyd}\left({\text{Na}}^{+}\right)}+\Delta {\text{H}}_{\text{hyd}\left({\text{cl}}^{-}\right)}=-179\text{ kcal}{\text{ m}}^{-1}$

$\Delta {\text{H}}_{\text{hyd}\left({\text{Na}}^{+}\right)}=-179\times \frac{6}{11}$

$=-97·64\text{ kcal}{\text{ m}}^{-1}$