A 50 mL of 1 M oxalic acid ( H 2 C 2 O 4 ⋅ 2 H 2 O ) is shaken with 0.5 gram of charcoal and so that after adsorption its final concentration changes to 0.5 M then the amount of oxalic acid in

Question

A 50 mL of 1 M oxalic acid ( H 2 ​ C 2 ​ O 4 ​ ⋅ 2 H 2 ​ O ) is shaken with 0.5 gram of charcoal and so that after adsorption its final concentration changes to 0.5 M then the amount of oxalic acid in grams adsorbed per gram of the charcoal is

TestHub · Accepted Answer

Δ n = ( M 1 ​ − M 2 ​ ) v = ( 1 − 0.5 ) 1000 50 ​ = 0.025 moles w OA ​ = Δ n × Mw = 0.025 × 126 = 3.15 gram, So 0.5gram of charcoal →3.15gram of acid w = ( 0.5 1 × 3.15 ​ ) = 6.30 gram / gram of charcoal

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