Chemistry - Surface Chemistry Question with Solution | TestHub

ChemistrySurface ChemistryColloids and their ClassificationsMedium2 minQB

ChemistryMediumsingle choice

Purple of cassious is formed on mixing :-

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Answer:

Solution:

The Purple of Cassius is a colloidal suspension of gold nanoparticles in tin(IV) oxide. It is formed when tin(II) chloride ( $S n C l_{2}$ ) reduces gold(III) chloride ( $A u C l_{3}$ ).

The reaction is:

$2 A u C l_{3} + 3 S n C l_{2} \to 2 A u (s) + 3 S n C l_{4}$

The finely divided gold particles, stabilized by $S n O_{2}$ , produce the characteristic purple color.

Therefore, mixing $S n C l_{2}$ and $A u C l_{3}$ forms the Purple of Cassius.

Stream:JEESubject:ChemistryTopic:Surface ChemistrySubtopic:Colloids and their Classifications

⏱ 2mℹ️ Source: QB

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