Adsorption of a gas follows Freundlich adsorption isotherm. $x$ is the mass of the gas adsorbed on mass $m$ of the adsorbent. The plot of $\frac{x}{m}$ versus $lo g p$ is shown in the given graph.
$\frac{x}{m}$ is proportional to :

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According to Freundlich adsorption isotherm m x ​ ∝ p n 1 ​ , m x ​ = k p n 1 ​ Slope = 3 2 ​ lo g m x ​ = lo g k + n 1 ​ lo g p Slope = n 1 ​ = 3 2 ​ m x ​ ∝ p 3 2 ​

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