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Chemistry - Surface Chemistry Question with Solution | TestHub

ChemistrySurface ChemistryGeneralEasy2 minPYQ_2020

ChemistryEasynumerical

Graph between $\log (\frac{x}{m}) v s \log P$ is provided for adsorption of $N H_{3}$ gas on metal surface. Calculate weight of $N H_{3}$ gas (in gm) absorbed by $24 g$ of metal surface at 2 atm pressure. (Take $\log 2 = 0.3$ )

Answer:

96.00

Solution:

Slope $= \frac{1}{n} = \tan 45^{o} = 1$
$\frac{x}{m} = K P^{\frac{1}{n}}$
$\log (\frac{x}{m}) = \log K + \frac{1}{n} \log P$
$= \log 2 + \frac{1}{n} \log 2$
$\log (\frac{x}{m}) = \log 2 + (1) \log (2)$
$\frac{x}{m} = 2 \times 2$
$\frac{x}{24} = 4$
$x = 4 \times 24 = 96 g$

Stream:NTA_ABHYASSubject:ChemistryTopic:Surface ChemistrySubtopic:General

⏱ 2mℹ️ Source: PYQ_2020

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