Chemistry - Surface Chemistry Question with Solution | TestHub

Millimoles$=10\times 10^{-3}=10^{-2}$

Moles$=10^{-5}$

No. of molecules$=6\times 10^{23}\times 10^{-5}=6\times 10^{18}$

Surface area ocupied by one molecule

$=\frac{0.24}{6\times 10^{18}}=0.04\times 10^{-18}\text{c}{\text{m}}^2$

$4\times 10^{-20}={\mathrm{x}}^2[\because \mathrm{x}=$edge length$]$

$\mathrm{x}=2\times 10^{-10}$cm$=2$pm