Chemistry - Surface Chemistry Question with Solution | TestHub

Negative colloid is coagulated by positive ion or vice-versa. Greater the valency of coagulating ion, greater will be coagulating power according to Hardy-Schulze rule.

$\left(\text{a}\right){\text{ZnSO}}_4\to {\text{Zn}}^{2+}+{\text{SO}}_4^{2-}$

$\left(\text{b}\right){\text{Na}}_3{\text{PO}}_4\to 3{\text{Na}}^{+}+{\text{PO}}_4^{3-}$

$\left(\text{c}\right){\text{AlCl}}_3\to {\text{Al}}^{3+}+3{\text{Cl}}^{-}$

$\left(\text{d}\right){\text{K}}_4\left[\text{Fe}{\left(\text{CN}\right)}_6\right]\to 4{\text{K}}^{+}+{\left[\text{Fe}{\left(\text{CN}\right)}_6\right]}^{4-}$

Since, in${\mathrm{A}\mathrm{l}\mathrm{C}\mathrm{l}}_3$, the valency of positive ion (coagulation ion) is highest, it is the most powerful coagulating agent among the given to coagulate the negative colloid.