Chemistry - STRUCTURAL ISOMERISM Question with Solution | TestHub

In reaction (1), cyclohexa-2,4-dien-1-one (the keto form) goes to phenol : the enol is aromatic, so the equilibrium lies overwhelmingly toward phenol - forward. In reaction (2), 1H-pyridin-4-one goes to 4-hydroxypyridine : here the keto form is the stable one (the amide-like C=O with N-H beats the aromatic hydroxypyridine), so the equilibrium lies backward (toward the keto form). Hence forward, backward.