Chemistry - STRUCTURAL ISOMERISM Question with Solution | TestHub

A terminal alkyne ${\mathrm{C}}_7{\mathrm{H}}_{12}$ has the form $\mathrm{HC}\equiv \mathrm{C}-{\mathrm{C}}_5{\mathrm{H}}_{11}$. The pentyl group has exactly eight isomers : n-pentyl, 1-methylbutyl, 2-methylbutyl, 3-methylbutyl, 1,1-dimethylpropyl, 1,2-dimethylpropyl, 2,2-dimethylpropyl and 1-ethylpropyl. Hence 8 distinct terminal alkynes.