Chemistry - STRUCTURAL ISOMERISM Question with Solution | TestHub

Pentan-2-one, CH₃-CO-CH₂-CH₂-CH₃, has two different alpha positions. Enolisation at the methyl gives one enol, CH₂=C(OH)-CH₂CH₂CH₃. Enolisation at the methylene gives CH₃-C(OH)=CH-CH₂CH₃, whose double bond carries two different groups on each carbon, so it exists as E and Z forms. Total = 1 + 2 = 3 enols.