Chemistry - STRUCTURAL ISOMERISM Question with Solution | TestHub

Z = 5. The compound is hept-5-en-3-one, $\mathrm{C}{\mathrm{H}}_3\mathrm{C}{\mathrm{H}}_2-\mathrm{CO}-\mathrm{CH}=\mathrm{CH}-\mathrm{C}{\mathrm{H}}_2-\mathrm{C}{\mathrm{H}}_3$. Exchangeable positions : the alpha $\mathrm{C}{\mathrm{H}}_2$ C-2 (2H), the alpha vinyl carbon C-4 (1H, through the enolate O-C=C-C=C), and the gamma $\mathrm{C}{\mathrm{H}}_2$ C-6 (2H, through the dienol O-C=C-C=C). The terminal methyl C-7 is beyond the gamma position and does not exchange. Total = 2 + 1 + 2 = 5.