Chemistry - STRUCTURAL ISOMERISM Question with Solution | TestHub

The compound is 4-methylpent-3-en-2-one (mesityl oxide), $\mathrm{C}{\mathrm{H}}_3-\mathrm{CO}-\mathrm{CH}=\mathrm{C}(\mathrm{C}{\mathrm{H}}_3{)}_2$. Exchangeable hydrogens : the alpha methyl C-1 (3H), the alpha vinylic carbon C-3 (1H), and - through the dienol O-C=C-C=C - the two gamma methyl groups on C-4 (6H). Total = 3 + 1 + 6 = 10.