The number of isomers of the aromatic compound C 8 H 10 is:

(i) D.U = C + 1 − ( H 2 ) = 8 + 1 − ( 10 2 ) = 4 Total number of aromatic isomers = 4.

Chemistry - STRUCTURAL ISOMERISM Question with Solution | TestHub

ChemistrySTRUCTURAL ISOMERISMFUCTIONAL ISOMERISMEasy2 minPYQ_2020

ChemistryEasysingle choice

The number of isomers of the aromatic compound C₈H₁₀is:

Answer:

Solution:

(i) $D.U = C + 1 - (\frac{H}{2}) = 8 + 1 - (\frac{10}{2})$

$= 4$

Total number of aromatic isomers = 4.

Stream:NTA_ABHYAS_NEETSubject:ChemistryTopic:STRUCTURAL ISOMERISMSubtopic:FUCTIONAL ISOMERISM

⏱ 2mℹ️ Source: PYQ_2020

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