V litre of SO 2 at 0 ∘ C and 1 atm is required to reduce 16.9 g of HCIO 3 to HCI . How many number of moles is '5V' litre of SO 2 at 273°C and 2 atm? R=0.0821 Latm/mol K

Question

V litre of SO 2 ​ at 0 ∘ C and 1 atm is required to reduce 16.9 g of HCIO 3 ​ to HCI . How many number of moles is '5V' litre of SO 2 at 273°C and 2 atm? R=0.0821 Latm/mol K

TestHub · Accepted Answer

Or 22.4 V ​ × 2 = 84.5 16.9 ​ × 6 ⇒ V = 13.44 L Now n ​ = RT P V ​ = 0.0821 × 546 2 × ( 5 × 13.44 ) ​ = 3

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