Chemistry - Stoichiometry Question with Solution | TestHub

Balanced reactions:

$3A+2B\to A_3{B}_2$

Given: $A=3mol$, $B=3mol$

For 1 mol $A_3{B}_2$, required $B=2mol$, so B is limiting.

$$Molesof{A}_3{B}_2=\frac{3}{2}=1.5mol$$

Second reaction:

$A_3{B}_2+C_2\to A_3{B}_2{C}_2$

Given $C=1mol$, so only 1 mol $A_3{B}_2$ reacts and forms:

$1mol{A}_3{B}_2{C}_2$

Remaining:

$1.5-1=0.5mol{A}_3{B}_2$

Therefore correct options:

(B) and (D)