Chemistry - Stoichiometry Question with Solution | TestHub

$\underset{100\mathrm{ml}}{\underbrace{{\mathrm{CS}}_2+\mathrm{CO}}}+\underset{200\mathrm{ml}}{{\mathrm{O}}_2}\to {\mathrm{CO}}_2+{\mathrm{SO}}_2$

${\mathrm{CS}}_2+3{\mathrm{O}}_2\to {\mathrm{CO}}_2+2{\mathrm{SO}}_2$

a ml

$\mathrm{CO}+1/2{\mathrm{O}}_2\to {\mathrm{CO}}_2$

$(100-a)\mathrm{ml}$

Volume of ${\mathrm{CO}}_2$ formed $=\mathrm{a}+(100-\mathrm{a})=100\mathrm{ml}$

Volume of ${\mathrm{SO}}_2$ formed $=2\mathrm{a}$

Volume of ${\mathrm{O}}_2$ used $=3\mathrm{a}+\frac{(100-\mathrm{a})}{2}$

Total volume after reaction $=245\mathrm{ml}$ $245=100+2\mathrm{a}+\left[200-3\mathrm{a}-\frac{(100-\mathrm{a})}{2}\right]$

${\mathrm{O}}_2$ left

$=300+2a-3a-50+\frac{a}{2}$

$\frac{\mathrm{a}}{2}=5$

$\mathrm{a}=10\mathrm{ml}$

Volume of ${\mathrm{CO}}_2$ formed $=100\mathrm{ml}$, volume of ${\mathrm{O}}_2$ left $=200-3\mathrm{a}-\left(\frac{100-\mathrm{a}}{2}\right)=125\mathrm{ml}$

$\mathrm{mol}\%$ of ${\mathrm{CS}}_2=\frac{10}{100}\times 100=10\%$