If specific rotation of glucose solution is 5 2 ∘ and that of fructose solution is − 9 2 ∘ then what will be the specific rotation of invert sugar?

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TestHub · Accepted Answer

Let 1 mole of sucrose be taken. On hydrolysis, one mole of glucose and one mole of fructose are formed.

Optical rotation per 2 moles of mixture is $1 \times 5 2^{\circ} + 1 \times (-9 2^{\circ}) = -4 0^{\circ}$ .

Hence, Optical rotation per 1 mole of mixture is $\frac{- 4 0 ^{\circ}}{2} = -2 0^{\circ}$ .

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