Draw all the geometrical isomers of hepta-2,4-diene and label each by the cis/trans and the E/Z system.

Question

TestHub · Accepted Answer

Hepta-2,4-diene, CH₃CH=CH-CH=CHCH₂CH₃, has two non-equivalent double bonds, so 2² = 4 geometrical isomers exist :

cis,cis-2,4-Heptadiene or (Z,Z)-2,4-Heptadiene :

structure

trans,cis-2,4-Heptadiene or (E,Z)-2,4-Heptadiene :

structure

cis,trans-2,4-Heptadiene or (Z,E)-2,4-Heptadiene :

structure

trans,trans-2,4-Heptadiene or (E,E)-2,4-Heptadiene :

structure

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