Consider following compounds :
If total number of meso form in compound (i) is x and optical active isomer of compound (ii) is y than find x + y

Question

Consider following compounds : If total number of meso form in compound (i) is x and optical active isomer of compound (ii) is y than find x + y

TestHub · Accepted Answer

Compound (i) is a symmetrical molecule with $n = 3$ chiral/pseudoasymmetric centers. The number of meso forms is $x = 2^{(n - 1) /2} = 2^{(3 - 1) /2} = 2^{1} = 2$ .

Compound (ii) is a symmetrical molecule with $n = 2$ chiral centers. The number of optically active isomers is $y = 2^{n - 1} = 2^{2 - 1} = 2^{1} = 2$ .

Therefore, the required sum is $x + y = 2 + 2 = 4.00$ .

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