An optically pure organic compound has specific rotation of + 4 0 ∘ C . The optical purity of the sample that exhibits specific rotation of + 3 2 ∘ is ____ %

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The optical purity is calculated by dividing the observed specific rotation by the specific rotation of the pure enantiomer, then multiplying by 100%.

Optical purity = $\frac{O b ser v e d s p ec i f i cro t a t i o n}{Sp ec i f i cro t a t i o n o f p u ree nan t i o m er} \times 100$

Optical purity = $\frac{+ 3 2 ^{\circ}}{+ 4 0 ^{\circ}} \times 100 = 80$ %

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