Chemistry - Solid State Question with Solution | TestHub

ChemistrySolid StateCubic CrystalsEasy2 minQB

ChemistryEasysingle choice

An element has a bcc structure with the cell edge 'a' pm. Density of element is ρ gm/cc. How many atoms are present in W gm of the element ?

Answer:

Solution:

Volume of one cell = $a^{3}$ × $1 0^{- 30}$ $cm^{3}$ , so mass of one cell = ρ $a^{3}$ × $1 0^{- 30}$ g.

Cells in W g = W/(ρ $a^{3}$ × $1 0^{- 30}$ ) = W × $1 0^{30} / (a^{3} ρ)$ .

bcc has 2 atoms per cell: atoms = 2 W × $1 0^{30} / (a^{3} ρ)$ .

Answer: (C).

Stream:JEESubject:ChemistryTopic:Solid StateSubtopic:Cubic Crystals

⏱ 2mℹ️ Source: QB

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