Chemistry - Solid State Question with Solution | TestHub

I (ZnS – zinc blende): fcc lattice with half tetrahedral voids occupied, equal Zn²⁺ and S²⁻ → matches R (fcc nearest distance = a√2/2) and S (equal cations & anions).

II (CaF₂ – fluorite): Ca²⁺ forms fcc lattice and all tetrahedral voids are occupied by F⁻ → matches Q, also follows R.

III (NaCl – rock salt): fcc lattice with octahedral voids occupied and equal ions → matches P, R, S.

IV (Diamond): pure covalent network (no ions/void filling like above), but still fcc-based lattice distance relation (R) applies.