In ionic solid, anions are arranged in hcp array and cations occupy $\frac{1}{2}$ tetrahedral voids. What is the formula of ionic compound ?
[Consider A = Cation ; B = anion]

Question

In ionic solid, anions are arranged in hcp array and cations occupy 2 1 ​ tetrahedral voids. What is the formula of ionic compound ? [Consider A = Cation ; B = anion]

TestHub · Accepted Answer

Let the number of anions (B) forming the hcp array be $N$ .

The total number of tetrahedral voids generated in the lattice is $2 N$ .

Since cations (A) occupy $\frac{1}{2}$ of the tetrahedral voids, the number of cations (A) is $\frac{1}{2} \times 2 N = N$ .

The ratio of the number of cations (A) to the number of anions (B) is $N : N = 1 : 1$ .

Therefore, the formula of the ionic compound is $AB$ .

Answer: $AB$

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