Chemistry - Solid State Question with Solution | TestHub

For a body-centered cubic (bcc) structure, the atoms touch each other along the body diagonal of the unit cell.

The relationship between the radius of the atom $r$ and the edge length of the unit cell $a$ is given by:

$4r=\sqrt{3}a$

Given $a=4.3\times 10^{-8}$ cm.

$r=\frac{\sqrt{3}}{4}\times 4.3\times 10^{-8}$ cm

$r=\frac{1.732}{4}\times 4.3\times 10^{-8}$ cm

$r=0.433\times 4.3\times 10^{-8}$ cm

$r=1.86\times 10^{-8}$ cm

Answer: $1.86\times 10^{-8}$ cm