Chemistry - Solid State Question with Solution | TestHub

The packing efficiency of a bcc unit cell is $68\%$.

Total volume occupied by all particles in the unit cell = $\frac{68}{100}\times V$

Total volume = $0.68\times 8.2\times 10^{-23}=5.576\times 10^{-23}{\mathrm{cm}}^3$

The number of particles per unit cell in a bcc structure is $2$.

Volume occupied by a single particle = $\frac{5.576\times 10^{-23}}{2}=2.788\times 10^{-23}{\mathrm{cm}}^3$

Answer: $2.788\times 10^{-23}{\mathrm{cm}}^3$