Chemistry - Solid State Question with Solution | TestHub

For a body-centered cubic (BCC) unit cell, the relationship between the atomic radius $r$ and the edge length $a$ is given by:

$r=\frac{\sqrt{3}}{4}a$

Given $a=287$ pm.

Substituting the value of $a$:

$r=\frac{1.732}{4}\times 287$

$r=0.433\times 287$

$r=124.27$ pm

Rounding to the nearest integer, the atomic radius is $124$ pm.

Answer: 124 pm