Chemistry - Solid State Question with Solution | TestHub

Let the number of atoms of element B forming the ccp structure be $N$.

The number of tetrahedral voids in the ccp structure is $2N$.

The atoms of element A occupy $\frac{1}{3}$ of the tetrahedral voids.

Number of atoms of A $=\frac{1}{3}\times 2N=\frac{2N}{3}$.

The ratio of atoms of A to B is $\frac{2N}{3}:N=2:3$.

The formula of the compound is $A_2{B}_3$.

Answer: ${\mathrm{A}}_2{\mathrm{B}}_3$