Chemistry - Solid State Question with Solution | TestHub

ChemistrySolid StateGeneralEasy2 minPYQ_2020

ChemistryEasysingle choice

The arrangement of $X^{-}$ ions around $A^{+}$ ion in solid $AX$ is given in the figure (not drawn to scale). If the radius of $X^{-}$ is $250 pm$ , the radius of $A^{+}$ is

Options:

Answer:

Solution:

$\frac{r_{A}^{+}}{r_{x}^{-}} = 0.414 = \frac{r_{A}^{+}}{250}$
$r_{A}^{+} = 0.414 \times 250 pm = 104 pm$

Stream:JEESubject:ChemistryTopic:Solid StateSubtopic:General

⏱ 2mℹ️ Source: PYQ_2020

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