Chemistry - Solid State Question with Solution | TestHub

In close packed lattice atoms$=\frac{\mathrm{N}\mathrm{c}}{8}+\frac{\mathrm{N}\mathrm{f}}{2}$
$=8\times \frac{1}{8}+6\times \frac{1}{2}=1+3=4$
Every constitute has 2 tetrahedral voids
So tetrahedral voids$=4\times 2=8$
Ratio will be 4 : 8 = 1 : 2.