What is the number of atoms present per unit cell of aluminium having edge length 4 A ∘ ? (If density of Al = 2 ⋅ 7 g cm − 3 , At. mass of Al = 27 )

a = 4 A ˚ = 4 × 1 0 − 8 cm , ρ = 2.7 g cm − 3 M = 27 , n = ? n = M ρ × a 3 × N A = 27 2.7 × ( 4 × 1 0 − 8 ) 3 × 6.022 × 1 0 23 = 3.85 ≈ 4

Start Free Mock LoginAlready registered? Login here

Chemistry - Solid State Question with Solution | TestHub

ChemistrySolid StateCubic CrystalsEasy2 minPYQ_2020

ChemistryEasysingle choice

What is the number of atoms present per unit cell of aluminium having edge length $4 A^{\circ}$ ? (If density of $Al = 2 \cdot 7 g cm^{- 3}$ , At. mass of $Al = 27$ )

Options:

Answer:

Solution:

$a = 4 \overset{˚}{A} = 4 \times 1 0^{- 8} cm, ρ = 2.7 g cm^{- 3}$ $M = 27, n = ?$ $n = \frac{ρ \times a ^{3} \times N _{A}}{M} = \frac{2.7 \times ( 4 \times 1 0 ^{- 8} ) ^{3} \times 6.022 \times 1 0 ^{23}}{27} = 3.85 \approx 4$

Stream:MHT_CETSubject:ChemistryTopic:Solid StateSubtopic:Cubic Crystals

⏱ 2mℹ️ Source: PYQ_2020

Doubts & Discussion

Loading discussions...