An element crystallises in bcc type having atomic radius 1 ⋅ 33 × 1 0 − 8 cm , the edge length of unit cell will be

For bcc crystal, r = 4 3 a ∴ a = 3 4 r = 1.732 4 × 1.33 × 1 0 − 8 cm ∴ a = 3.07 × 1 0 − 8 cm .

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ChemistrySolid StateCubic CrystalsEasy2 minPYQ_2020

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An element crystallises in bcc type having atomic radius $1 \cdot 33 \times 1 0^{- 8} cm$ , the edge length of unit cell will be

Answer:

Solution:

For bcc crystal, $r = \frac{3}{4} a$ $∴ a = \frac{4 r}{3} = \frac{4 \times 1.33 \times 1 0 ^{- 8} cm}{1.732}$ $∴ a = 3.07 \times 1 0^{- 8} cm .$

Stream:MHT_CETSubject:ChemistryTopic:Solid StateSubtopic:Cubic Crystals

⏱ 2mℹ️ Source: PYQ_2020

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