Chemistry - Solid State Question with Solution | TestHub

In body centered cubic lattice, oppositely charged ions touch each other along the cube
$2{\mathrm{r}}_{\mathrm{c}}+2{\mathrm{r}}_{\mathrm{a}}=\sqrt{3}\mathrm{a}$
${\mathrm{r}}_{\mathrm{c}}+{\mathrm{r}}_{\mathrm{a}}=\frac{\sqrt{3}}{2}\mathrm{a}$
$=\frac{\sqrt{3}}{2}\times 387=335.15\mathrm{}\mathrm{p}\mathrm{m}$
given${\mathrm{r}}_{\mathrm{a}}=181\mathrm{}\mathrm{p}\mathrm{m}$
${\mathrm{r}}_{\mathrm{c}}=335.15-181.0=154.15\mathrm{}\mathrm{p}\mathrm{m}$