Chemistry - Solid State Question with Solution | TestHub

In$\mathrm{F}\mathrm{C}\mathrm{C}$arrangement surface diagonal is given by$\sqrt{2}\mathrm{a}$
Hence,$4\mathrm{r}=\sqrt{2}\mathrm{a}$
$\mathrm{r}=\frac{\mathrm{a}}{2\sqrt{2}}$;$\mathrm{r}=\frac{620}{2\sqrt{2}}=\mathrm{219.25 }\mathrm{}\mathrm{p}\mathrm{m}$