A metal has a fcc lattice. The edge length of unit is 404pm.The density of metal is 2.72 g/cm 3 . The molar mass of the metal is (N A, Avagadro's constant = 6.02 × 1 0 23 )

As ρ = z × m N A × ( a ) 3 2.72 = 4 × m 6.02 × 1 0 23 × ( 4.04 × 1 0 - 8 ) 3 On solving m = 27 g / m o l

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Chemistry - Solid State Question with Solution | TestHub

ChemistrySolid StateMiscellaneous/MixedEasy2 minPYQ_2020

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A metal has a fcc lattice. The edge length of unit is 404pm.The density of metal is 2.72 g/cm³. The molar mass of the metal is
(N_A,Avagadro's constant $= 6.02 \times 1 0^{23}$ )

Options:

Answer:

Solution:

As $ρ = \frac{z \times m}{N_{A} \times (a)^{3}}$
$2.72 = \frac{4 \times m}{6.02 \times 1 0^{23} \times (4.04 \times 1 0^{- 8})^{3}}$
On solving $m = 27 g / m o l$

Stream:NTA_ABHYAS_NEETSubject:ChemistryTopic:Solid StateSubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: PYQ_2020

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