Chemistry - Solid State Question with Solution | TestHub

Suppose number of${\mathrm{B}}^{-}$ions$=\mathrm{N}$
So number of tetrahedral holes$=2\mathrm{N}$
As 25% tetrahedral holes are occupied by${\mathrm{A}}^{+}$ions.
So number of${\mathrm{A}}^{+}$ions$=\frac{2\mathrm{N}}{4}=\frac{\mathrm{N}}{2}$
So ratio of${\mathrm{A}}^{+}:{\mathrm{B}}^{-}=\frac{\mathrm{N}}{2}:\mathrm{N}$
1:2
So the formula is$\mathrm{A}{\mathrm{B}}_2$