Chemistry - Solid State Question with Solution | TestHub

ChemistrySolid StateGeneralEasy2 minPYQ_2020

ChemistryEasynumerical

A crystalline solid of a pure substance has a face-centred cubic structure with a cell edge of 400 pm. If the density of the substance in the crystal is 8 g $c m^{- 3}$ , then the number of atoms present in 256 g of the crystal is $N \times 1 0^{24}$ . The value of N is

Answer:

2.00

Solution:

$d = \frac{Z \times \frac{M_{0}}{N_{A}}}{a^{3}}$

(d = density)

$8 = \frac{4 \times \frac{M_{0}}{6 \times 1 0^{23}}}{(4 \times 1 0^{- 10})^{3}}$

$M_{0} = \frac{1}{8 \times 6 \times 1.6}$

Number of moles in 256 g $= \frac{256}{8 \times 6 \times 1.6} = \frac{10}{3}$

Number of atoms $= \frac{10}{3} \times 6 \times 1 0^{23} = 2 \times 1 0^{24}$

Stream:JEESubject:ChemistryTopic:Solid StateSubtopic:General

⏱ 2mℹ️ Source: PYQ_2020

Doubts & Discussion

Loading discussions...